arrays - Function with loop calling same function in PHP -

i'm having trouble. trying make work long time, decided ask here.

i have arrays inside it:

$myarray = [ ['string1','string2'], ['string3','string4'], ['string5',['string6','string7','string99']], ['string8','string9'] ]; 

i making function search s

function searcharray($array,$chave,$id) {     foreach ($array $key) {            if (is_array($key)) {              if (($key[0] == $chave) && ($key[1] == $id)) {               break;             }                  else {                searcharray($key,$chave,$id);                }            }    }      return $key; }   $result = searcharray($myarray,'string6','string7'); print_r($result); 

it supposed print ['string6','string7','string99']] it printing last "key" of array: ['string8','string9']

the break not working. after break, continue checking next arrays.

with these modification returns expected values:

<?php   $myarray = [ ['string1','string2'], ['string3','string4'], ['string5',['string6','string7','string99']], ['string8','string9'] ];  function searcharray($array,$chave,$id) {      foreach ($array $key) {         if (is_array($key)) {             if (($key[0] == $chave) && ($key[1] == $id)) {                 return $key;             } else {                 $res = searcharray($key,$chave,$id);                 if($res !== false) {                     return $res;                 }             }         }     }      return false; }   $result = searcharray($myarray,'string6','string7'); print_r($result); 

the failure break on success. makes no sense.

you need return value on success. if no success return false. imagine may happen searched values not been found should return false.