android - show only one of similar items in List -

i have list of numbers this:

-153 -542 -153 -153 -783 -785 -975 -153 -478 

as see "153" showen 4 times want show number 1 time this:

-153 -542 -783 -785 -975 -478 

edit:

i need messages numbers show 1 if similar numbers here method:

    public static list<smsdata> getallnumbers(context context){      list<smsdata> smslist = new arraylist<smsdata>();      uri uri = uri.parse("content://sms/inbox");     cursor c= context.getcontentresolver().query(uri, null,null,null,null);      // read sms data , store in list     if(c.movetofirst()) {         for(int i=0; < c.getcount(); i++) {              smsdata sms = new smsdata();             sms.setbody(c.getstring(c.getcolumnindexorthrow("body")).tostring());             sms.setnumber(c.getstring(c.getcolumnindexorthrow("address")).tostring());             sms.setdate(c.getstring(c.getcolumnindexorthrow("date")).tostring());             smslist.add(sms);               c.movetonext();         }     }     return smslist; } 

i fond solution:

https://stackoverflow.com/a/19305534/3522182

tnx all.

    arraylist yourlist = new arraylist(); /* add values list */     arraylist simplelist = new arraylist();      hashset hashset = new hashset();     hashset.addall(yourlist);      simplelist.addall(hashset);// list has unique numbers 

note: order here unexpected. if want orderd, use linkedhashset keeping same order.