python - Should every url from urls.py in django have it's own method to respond the request? -

my test site has several search pages , each page contains it's own search form. of these pages identical , displaying functions in views.py similar.

for example:

@csrf_exempt def rooms(request):     submited = false     search_option = 'none'     search_param = 'none'     data = []     query = ''      try:         cnx = mysql.connector.connect(user='root', password='****', host='127.0.0.1', database='lessons')         cursor = cnx.cursor()          if not submited:             query = "select * rooms;"             cursor.execute(query)             data = cursor.fetchall()          if request.method == 'post':             submited = true             if request.post['search_option'] != "" , request.post['search_param'] != "":                 search_option = request.post['search_option']                 search_param = request.post['search_param']                 query = "select * rooms " + search_option + " = " + search_param + ';'                 cursor.execute(query)                 data = cursor.fetchall()      except mysql.connector.error err:         if err.errno == errorcode.er_access_denied_error:             print("something wrong user name or password")         elif err.errno == errorcode.er_bad_db_error:             print("database not exist")         else:             print(err)      return render(request, "rooms.html",                   {"page_name": "rooms", "search_option": search_option, "search_param": search_param,                    "submited": submited, "dbdata": data, "query": query})  @csrf_exempt def teachers(request):     submited = false     search_option = 'none'     search_param = 'none'     data = []      try:         cnx = mysql.connector.connect(user='root', password='****', host='127.0.0.1', database='lessons')         cursor = cnx.cursor()          if submited == false:             query = "select * teachers;"             cursor.execute(query)             data = cursor.fetchall()          if request.method == 'post':             submited = true             if 'search_option' in request.post , 'search_param' in request.post:                 search_option = request.post['search_option']                 search_param = request.post['search_param']                 query = "select * teachers " + search_option + " = '" + search_param + "';"                 cursor.execute(query)                 data = cursor.fetchall()      except mysql.connector.error err:         if err.errno == errorcode.er_access_denied_error:             print("something wrong user name or password")         elif err.errno == errorcode.er_bad_db_error:             print("database not exist")         else:             print(err)      return render(request, "teachers.html",                   {"page_name": "teachers", "search_option": search_option, "search_param": search_param,                    "submited": submited, "dbdata": data, "query": query}) 

i wondering how make several similar search urls (with small changes, in case it's different initial sql-query display general results) refer 1 function (maybe due if statement decide page display) rather several quite identical , avoid code repetition.

urls.py

urlpatterns = patterns('',                        url(r'rooms', 'lessons.views.rooms', name='rooms'),                        url(r'teachers', 'lessons.views.teachers', name='teachers'),                        url(r'subjects', 'lessons.views.subjects', name='subjects')) 

thanks in advance.

you can use same view function, let's lessons.views.generic_view, each url , can discriminate based on view's name this:

from django.core.urlresolvers import resolve  def generic_view(request):     view_name = resolve(request.path).view_name     if view_name == 'teachers':          ... 

your sample urls.py:

urlpatterns = patterns('',     url(r'rooms', 'lessons.views.generic_view', name='rooms'),     url(r'teachers', 'lessons.views.generic_view', name='teachers'),     url(r'subjects', 'lessons.views.generic_view', name='subjects') )