python - Check if string contains list item -

i have following script check if string contains list item:

word = ['one',         'two',         'three'] string = 'my favorite number two' if any(word_item in string.split() word_item in word):     print 'string contains word word list: %s' % (word_item) 

this works, i'm trying print list item(s) string contains. doing wrong?

the problem you're using if statement instead of for statement, print runs (at most) once (if @ least 1 word matches), , @ point, any has run through whole loop.

this easiest way want:

words = ['one',          'two',          'three'] string = 'my favorite number two' word in words:     if word in string.split():         print('string contains word word list: %s' % (word)) 

if want functional reason, this:

for word in filter(string.split().__contains__, words):     print('string contains word word list: %s' % (word)) 

since bound answer performance-related answer though question has nothing performance, more efficient split string once, , depending on how many words want check, converting set might useful.

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regarding question in comments, if want multi-word "words", there 2 easy options: adding whitespace , searching words in full string, or regular expressions word boundaries.

the simplest way add space character before , after text search , search ' ' + word + ' ':

phrases = ['one',            'two',            'two words'] text = "this has 2 words in it"  phrase in phrases:     if " %s " % phrase in text:         print("text '%s' contains phrase '%s'" % (text, phrase)) 

for regular expressions, use \b word boundary:

import re  phrase in phrases:     if re.search(r"\b%s\b" % re.escape(phrase), text):         print("text '%s' contains phrase '%s'" % (text, phrase)) 

which 1 "nicer" hard say, regular expression less efficient (if matters you).

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and if don't care word boundaries, can do:

phrases = ['one',            'two',            'two words'] text = "the word 'tone' matched, 'two words'"  phrase in phrases:     if phrase in text:         print("text '%s' contains phrase '%s'" % (text, phrase))