Finding strings in a file using regex and grep in Linux -

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i trying find proper regexes use grep command on file text.txt.

question

  1. find occurrences of words in text have substring ad, bd, cd, dd, ed.

  2. find occurrences of numbers > 100

  3. find occurrences of numbers > 100 contain digit 0 or 5

my approach

  1. grep -io '[a-e]*d' text

    prints words proper substrings, doesn’t print whole string/word.

    ad d d ed d d ed d d d d ed d d

  2. grep -io '[199][1-9]*' text

    i believe way off on regex, still prints correct result.

    1973 197 17775

  3. grep -io '[05][1-9]*' text

    this continuation of 2., don’t understand 2. part in 3., believe have string containing digit 0 or 5 correct.

    0 0 0 5

a) find occurrences of words in text have substring ad, bd, cd, dd, ed.

grep -ow '.*\(a\|b\|c\|d\|e\)d.*' text

or

egrep -ow '.*(a|b|c|d|e)d.*' text

b) find occurrences of numbers > 100

grep -ow '[1-9][0-9][0-9]\+' text

c) find occurrences of numbers > 100 contain digit 0 or 5

grep -ow '[1-9][0-9][0-9]\+' text | grep '\(0\|5\)'

or

grep -ow '[1-9][0-9][0-9]\+' text | egrep '(0|5)'

i'm using option -o output every match on it's own line , not whole line pattern found , option -w specifies before , after match should word boundary.


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