debugging - Viewing Swift optional values in debugger -

trying feet wet in writing , debugging swift code, wrote following. on os x 10.10.2, xcode 6.2.

let text : string? = "this text.\njust fun."  let lines : [string]? =     text?.componentsseparatedbycharactersinset(         nscharacterset.newlinecharacterset())  println("\(lines)") 

breaking on println ... line, debugger's variable view shows some value of lines. in understanding, indicates lines of optional type , contains value wrapped in some, opposed being none.

knowing that, how can use debugger inspect value is? tried:

• clicking small "i" button, produces output "some" in debugger console.
• entering po lines , po lines! in debugger console, yields exc_bad_access. update: following fresh installation of xcode, po lines seems have no effect, i.e. no output.

the final line prints optional(["this text.", "just fun."]), i'd debugger show.

how can @ unwrapped string array value of lines, , difference between optional variable lines, unwrapped value debugger doesn't show, , optional variable text, value show? have introduce auxiliary variable every time want debug optional value, or use printf-debugging?

maybe misunderstanding, made "lines" optional value. because of that, need unwrap in println statement or not make optional value. take off "?" after "lines" declaration first , see if works you.

let lines : [string] =